Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy.
x^4y^2 鈭?x^3(y) + 5xy^3 = 0Regard y as the independent variable and x as the dependent variable and use implicit differentiation?
(4x鲁)(dx/dy)y虏 + (2y)(x^4) - [3x虏(dx/dy)y] + x鲁] + 5(dx/dy)y鲁 + (3y虏)(5x) = 0
[ 4x鲁 y 虏 - 3x虏y + 5y鲁 ] dx/dy = x鲁 - 15xy虏 - 2y x^4
dx/dy = [ x鲁 - 15xy虏 - 2y x^4 ] / [ 4x鲁 y 虏 - 3x虏y + 5y鲁 ]
Anywhere near answer?
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